8y^2-41y+5=

Solution for 8y^2-41y+5= equation:

Simplifying
8y2 + -41y + 5 = 0

Reorder the terms:
5 + -41y + 8y2 = 0

Solving
5 + -41y + 8y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + -8y)(5 + -1y) = 0

Subproblem 1
Set the factor '(1 + -8y)' equal to zero and attempt to solve:

Simplifying
1 + -8y = 0

Solving
1 + -8y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -8y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -8y = 0 + -1
-8y = 0 + -1

Combine like terms: 0 + -1 = -1
-8y = -1

Divide each side by '-8'.
y = 0.125

Simplifying
y = 0.125
Subproblem 2
Set the factor '(5 + -1y)' equal to zero and attempt to solve:

Simplifying
5 + -1y = 0

Solving
5 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1y = 0 + -5
-1y = 0 + -5

Combine like terms: 0 + -5 = -5
-1y = -5

Divide each side by '-1'.
y = 5

Simplifying
y = 5
Solution
y = {0.125, 5}